2017年4月13日 星期四

[LeetCode] 133. Clone Graph

轉自LeetCode

Clone an undirected graph. Each node in the graph contains a label and a list of its neighbors.

OJ's undirected graph serialization:
Nodes are labeled uniquely.
We use # as a separator for each node, and , as a separator for node label and each neighbor of the node.
As an example, consider the serialized graph {0,1,2#1,2#2,2}.
The graph has a total of three nodes, and therefore contains three parts as separated by #.
  1. First node is labeled as 0. Connect node 0 to both nodes 1 and 2.
  2. Second node is labeled as 1. Connect node 1 to node 2.
  3. Third node is labeled as 2. Connect node 2 to node 2 (itself), thus forming a self-cycle.

Visually, the graph looks like the following:
       1
      / \
     /   \
    0 --- 2
         / \
         \_/
<Solution>
這題的題意其實就是要做 deep copy,即要完整複製一份 undirected graph

有DFS和BFS兩種解法,這次使用 DFS 來解

想法如下
  • 因為題目有說,每個 label 都是唯一的,所以使用一個 hash map 來記錄已經創好的 node,避免創建出多餘的node
  • 用 DFS 去處理 neighbors 的拷貝。先把一條完整的 path 串完,再回頭找下一條
code 如下(參考資料)
c++

kotlin

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