Given a binary array, find the maximum number of consecutive 1s in this array.
Example 1:
Input: [1,1,0,1,1,1] Output: 3 Explanation: The first two digits or the last three digits are consecutive 1s. The maximum number of consecutive 1s is 3.
Note:
- The input array will only contain
0 and1 . - The length of input array is a positive integer and will not exceed 10,000
這題不難,直接照題意寫個O(n)的解法就會過
參考了一個解法,更加簡潔
主要想法就是,遇到0,重置 count 就行
code 如下
C++
code 如下
C++
kotlin
沒有留言:
張貼留言