[LeetCode] 557. Reverse Words in a String III

轉自LeetCode

Given a string, you need to reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order.

Example 1:

Input: "Let's take LeetCode contest"
Output: "s'teL ekat edoCteeL tsetnoc"

Note: In the string, each word is separated by single space and there will not be any extra space in the string.

<Solution>

想法如下

• 利用空白來切割字串

• 反轉切割出來的子字串，再串起來

code 如下

C++

	class Solution {
	public:
	string reverseWords(string s) {
	istringstream iss(s);
	ostringstream oss;
	string word;
	while(iss >> word) {
	reverse(word.begin(), word.end());
	oss << word << " ";
	}
	string ans = oss.str();
	ans.pop_back();
	return ans;
	}
	};

view raw reverseWordsInTheString.cpp hosted with ❤ by GitHub

Java

	class Solution {
	public String reverseWords(String s) {
	String[] words = s.split(" ");
	for(int i = 0; i < words.length; ++i) {
	words[i] = new StringBuilder(words[i]).reverse().toString();
	}
	StringBuilder sb = new StringBuilder();
	for(final String str: words) {
	sb.append(str);
	sb.append(" ");
	}
	return sb.toString().trim();
	}
	}

view raw reverseWordsInTheString.java hosted with ❤ by GitHub