Given an array of distinct integers
The answer is guaranteed to fit in a 32-bit integer.
Example 1:
Input: nums = [1,2,3], target = 4 Output: 7 Explanation: The possible combination ways are: (1, 1, 1, 1) (1, 1, 2) (1, 2, 1) (1, 3) (2, 1, 1) (2, 2) (3, 1) Note that different sequences are counted as different combinations.
Example 2:
Input: nums = [9], target = 3 Output: 0
Constraints:
1 <= nums.length <= 200 1 <= nums[i] <= 1000 - All the elements of
nums are unique. 1 <= target <= 1000
Follow up: What if negative numbers are allowed in the given array? How does it change the problem? What limitation we need to add to the question to allow negative numbers?
求排列組合,第一個想到的就是 DFS
然後可以看到 (1,1,2) 和 (2,1,1) 被視作不同的答案
直接用 DFS 求會 TLE,所以借用個 HashMap 來剪枝
如果 map 裡面已經有答案了,就回傳答案,不用再找下去
kotlin
沒有留言:
張貼留言