Given an array of integers
A triplet
0 <= i < j < k < arr.length |arr[i] - arr[j]| <= a |arr[j] - arr[k]| <= b |arr[i] - arr[k]| <= c
Where
Return the number of good triplets.
Example 1:
Input: arr = [3,0,1,1,9,7], a = 7, b = 2, c = 3 Output: 4 Explanation: There are 4 good triplets: [(3,0,1), (3,0,1), (3,1,1), (0,1,1)].
Example 2:
Input: arr = [1,1,2,2,3], a = 0, b = 0, c = 1 Output: 0 Explanation: No triplet satisfies all conditions.
Constraints:
3 <= arr.length <= 100 0 <= arr[i] <= 1000 0 <= a, b, c <= 1000
Solution
原本的想法是要用 DFS 去找出所有的組合
但寫起來又怪怪的,條件檢查有點複雜,這題又是 easy
後來發現,就真的照題意做就可以了
kotlin(參考解答)
沒有留言:
張貼留言