2018年6月6日 星期三

[LeetCode] 230. Kth Smallest Element in a BST

轉自LeetCode

Given a binary search tree, write a function kthSmallest to find the kth smallest element in it.
Note: 
You may assume k is always valid, 1 ≤ k ≤ BST's total elements.
Example 1:
Input: root = [3,1,4,null,2], k = 1
Output: 1
Example 2:
Input: root = [5,3,6,2,4,null,null,1], k = 3
Output: 3
Follow up:
What if the BST is modified (insert/delete operations) often and you need to find the kth smallest frequently? How would you optimize the kthSmallest routine?
<Solution>

想法如下
  • 因為 BST 的特性,用 inorder 歷遍的話,數字剛好會是從最小到最大
  • 檢查目前的節點,是不是剛好就是指定的第 k 個
code 如下

Java(參考解答)

kotlin

沒有留言:

張貼留言