We are given two strings, A and B .
A shift on A consists of taking string A and moving the leftmost character to the rightmost position. For example, if A = 'abcde' , then it will be 'bcdea' after one shift on A . Return True if and only if A can become B after some number of shifts on A .
Example 1: Input: A = 'abcde', B = 'cdeab' Output: true Example 2: Input: A = 'abcde', B = 'abced' Output: false
Note:
A andB will have length at most100 .
想法如下
- 因為是 shift 的方式來產生不同字串,所以新字串一定會是 A+A 這個字串裡面的 substring
- 首先,檢查長度是不是相同,不同,那一定不可能。相同,再檢查 B 是不是 A+A 裡面的子字串
code 如下
Java
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