Given an array consisting of n integers, find the contiguous subarray of given length k that has the maximum average value. And you need to output the maximum average value.
Example 1:
Input: [1,12,-5,-6,50,3], k = 4 Output: 12.75 Explanation: Maximum average is (12-5-6+50)/4 = 51/4 = 12.75
Note:
- 1 <=
k <=n <= 30,000. - Elements of the given array will be in the range [-10,000, 10,000].
想法如下
- 可以不用管平均,只要找到指定長度下,總和最大的 subarray 就是所求
- 利用 slicing window 的概念,先計算 1 到 k 這個 subarray 的和(sum),之後如果要計算 2 到 k+1 的和,就是 sum + nums[k+1] - nums[1]
Java(參考解答)
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