2018年6月20日 星期三

[LeetCode] 844. Backspace String Compare

轉自LeetCode

Given two strings S and T, return if they are equal when both are typed into empty text editors. # means a backspace character.
Example 1:
Input: S = "ab#c", T = "ad#c"
Output: true
Explanation: Both S and T become "ac".
Example 2:
Input: S = "ab##", T = "c#d#"
Output: true
Explanation: Both S and T become "".
Example 3:
Input: S = "a##c", T = "#a#c"
Output: true
Explanation: Both S and T become "c".
Example 4:
Input: S = "a#c", T = "b"
Output: false
Explanation: S becomes "c" while T becomes "b".
Note:
  1. 1 <= S.length <= 200
  2. 1 <= T.length <= 200
  3. S and T only contain lowercase letters and '#' characters.
Follow up:
  • Can you solve it in O(N) time and O(1) space?
<Solution>

想法如下
  • 用 stack 來組出最後的字串,然後再比較兩個最後的字串是不是一樣
code 如下

Java

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