You're given strings J representing the types of stones that are jewels, and S representing the stones you have. Each character in S
is a type of stone you have. You want to know how many of the stones you have are also jewels.
The letters in J are guaranteed distinct, and all characters in J and S are letters. Letters are case sensitive, so "a" is considered a different type of stone from "A" .
Example 1:
Input: J = "aA", S = "aAAbbbb" Output: 3
Example 2:
Input: J = "z", S = "ZZ" Output: 0
Note:
S andJ will consist of letters and have length at most 50.- The characters in
J are distinct.
想法如下
- 用個 HashSet 把 J 存起來,然後歷遍 S 檢查有幾個字元是在 HashSet 裡面
Java
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